SEATTLE -- The Seattle Seahawks and Jamal Adams have agreed to a four-year extension that makes him the NFL's highest-paid safety, a source told ESPN's Adam Schefter on Tuesday.
Adams' deal carries a max value of $72 million, a $20 million signing bonus and $38 million guaranteed, the source told Schefter.
He reported on time for training camp but has not taken part in any practices or games, watching from the sideline while appearing engaged and in good spirits. The agreement ends the three-week stalemate with the Seahawks, who open their season on Sept.