SEATTLE -- The Seattle Seahawks have signed Jamal Adams to a four-year extension that makes him the NFL's highest-paid safety, the team announced Tuesday.
Adams' deal has a max value of $72 million, a $20 million signing bonus and $38 million guaranteed, agents Kevin Conner and Robert Brown of Universal Sports told ESPN's Adam Schefter on Tuesday.
"We officially signed. I'm excited to be here," Adams said in a video posted to the Seahawks' Twitter feed. "It's going to be a wonderful journey, man. The next thing on our mind is getting that [championship] -- getting right back to it and going to get it.