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Saquon Barkley Wins 2024-25 NFL Offensive Player of the Year Award over Lamar, Chase

Philadelphia Eagles running back Saquon Barkley has won the Associated Press Offensive Player of the Year award for the first time.

Rob Maaddi of the Associated Press revealed the voting results. Barkley won 35 of 50 first-place votes to win the award with ease.

The award was announced during the annual NFL Honors event, which took place Thursday in New Orleans, home of this year's Super Bowl.

Barkley earned the honor over four fellow finalists: Cincinnati Bengals wide receiver Ja'Marr Chase, Bengals quarterback Joe Burrow, Baltimore Ravens quarterback Lamar Jackson and Ravens running back Derrick Henry.