Former Tampa Bay Buccaneers linebacker Kwon Alexander reportedly signed with the San Francisco 49ers Monday on a four-year, $54 million deal, according to Ian Rapoport of NFL.com.
Adam Schefter of ESPN reported the deal includes $27 million in guaranteed money.
The 24-year-old saw his 2018 season end in disappointment with a torn ACL after just six games. When he was on the field, he notched 45 tackles, a sack and two forced fumbles in six games, his first season with fewer than 90 tackles.
In his first three seasons, Alexander proved to be a tackling machine, accumulating 335 tackles, six sacks, six interceptions, four forced fumbles and two fumble recoveries.