FOXBOROUGH, Mass. - New England Patriots tight end Rob Gronkowski earned first-team All-Pro honors, which earns him $2.5 million and achieves the highest level of incentives possible as part of the revamped contract he signed last offseason.
When the season began, Gronkowski had a chance to earn an additional $5.5 million in incentives based on a combination of postseason honors, playing time and statistical production.
To reach the top tier of incentives, he had to be named first-team All-Pro, play at least 90 percent of the offensive snaps or reach 80 receptions or 1,200 receiving yards.