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Jameis Winston has been named AFC Offensive Player of the Week, the NFL announced Wednesday, becoming the first Cleveland Browns quarterback to win the award in four years.
Winston, making his first start since Sept. 25, 2022, passed for 334 yards and three touchdowns in the Browns' 29-24 upset victory over the Baltimore Ravens. Winston set a franchise record for passing yards in a Browns starting debut and tossed the go-ahead touchdown with 59 seconds remaining.
It marks Winston's first Player of the Week award since Week 4 of the 2019 season, when he was a member of the Tampa Bay Buccaneers.